| On Diophantine Equation X（ X ＋ 1 ） （ X ＋ 2） （ X ＋ 3） = 14Y（Y＋1）（Y＋2）（Y＋3） |
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| 引用本文： | 段辉明,郑继明.On Diophantine Equation X（ X ＋ 1 ） （ X ＋ 2） （ X ＋ 3） = 14Y（Y＋1）（Y＋2）（Y＋3）[J].西南交通大学学报(英文版),2009,17(1):90-93. |
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| 作者姓名： | 段辉明 郑继明 |
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| 作者单位： | College of Mathematics and Physics,Chongqing University of Posts and Telecommunications,Chongqing 400065,China |
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| 基金项目： | 重庆邮电大学校科研和教改项目 |
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| 摘 要： |
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| 关 键 词： | 整数解 丢番图方程 返回序列 二次方程残数 |
On Diophantine Equation X(X+1)(X+2)(X+3)=14Y(Y+1)(Y+2)(Y+3) |
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| DUAN Hui-ming,ZHENG Ji-ming.On Diophantine Equation X(X+1)(X+2)(X+3)=14Y(Y+1)(Y+2)(Y+3)[J].Journal of Southwest Jiaotong University,2009,17(1):90-93. |
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| Authors: | DUAN Hui-ming ZHENG Ji-ming |
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| Institution: | College of Mathematics and Physics,Chongqing University of Posts and Telecommunications,Chongqing 400065,China |
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| Abstract: | The Diophantine equation X(X+1)(X+2)(X+3)=14Y(Y+1)(Y+2)(Y+3) still remains open.Using recurrence sequence,Maple software,Pell equation and quadraric residue,this paper proved it has only two positive integer solutions,i.e.,(X,Y)=(5,2),(7,3). |
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| Keywords: | Integer solution Diophantine equation Recurrent sequence Quadratic residue |
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